Optimal. Leaf size=288 \[ \frac {\left (a^2-2 a b-b^2\right ) \sqrt {e} \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} d}-\frac {\left (a^2-2 a b-b^2\right ) \sqrt {e} \text {ArcTan}\left (1+\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} d}-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}-\frac {\left (a^2+2 a b-b^2\right ) \sqrt {e} \log \left (\sqrt {e}+\sqrt {e} \cot (c+d x)-\sqrt {2} \sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d}+\frac {\left (a^2+2 a b-b^2\right ) \sqrt {e} \log \left (\sqrt {e}+\sqrt {e} \cot (c+d x)+\sqrt {2} \sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d} \]
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Rubi [A]
time = 0.19, antiderivative size = 288, normalized size of antiderivative = 1.00, number of steps
used = 12, number of rules used = 9, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.360, Rules used = {3624, 3609,
3615, 1182, 1176, 631, 210, 1179, 642} \begin {gather*} \frac {\sqrt {e} \left (a^2-2 a b-b^2\right ) \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} d}-\frac {\sqrt {e} \left (a^2-2 a b-b^2\right ) \text {ArcTan}\left (\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}+1\right )}{\sqrt {2} d}-\frac {\sqrt {e} \left (a^2+2 a b-b^2\right ) \log \left (\sqrt {e} \cot (c+d x)-\sqrt {2} \sqrt {e \cot (c+d x)}+\sqrt {e}\right )}{2 \sqrt {2} d}+\frac {\sqrt {e} \left (a^2+2 a b-b^2\right ) \log \left (\sqrt {e} \cot (c+d x)+\sqrt {2} \sqrt {e \cot (c+d x)}+\sqrt {e}\right )}{2 \sqrt {2} d}-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1182
Rule 3609
Rule 3615
Rule 3624
Rubi steps
\begin {align*} \int \sqrt {e \cot (c+d x)} (a+b \cot (c+d x))^2 \, dx &=-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}+\int \sqrt {e \cot (c+d x)} \left (a^2-b^2+2 a b \cot (c+d x)\right ) \, dx\\ &=-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}+\int \frac {-2 a b e+\left (a^2-b^2\right ) e \cot (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx\\ &=-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}+\frac {2 \text {Subst}\left (\int \frac {2 a b e^2-\left (a^2-b^2\right ) e x^2}{e^2+x^4} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{d}\\ &=-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}-\frac {\left (\left (a^2-2 a b-b^2\right ) e\right ) \text {Subst}\left (\int \frac {e+x^2}{e^2+x^4} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{d}+\frac {\left (\left (a^2+2 a b-b^2\right ) e\right ) \text {Subst}\left (\int \frac {e-x^2}{e^2+x^4} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{d}\\ &=-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}-\frac {\left (\left (a^2+2 a b-b^2\right ) \sqrt {e}\right ) \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}+2 x}{-e-\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d}-\frac {\left (\left (a^2+2 a b-b^2\right ) \sqrt {e}\right ) \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}-2 x}{-e+\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d}-\frac {\left (\left (a^2-2 a b-b^2\right ) e\right ) \text {Subst}\left (\int \frac {1}{e-\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{2 d}-\frac {\left (\left (a^2-2 a b-b^2\right ) e\right ) \text {Subst}\left (\int \frac {1}{e+\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{2 d}\\ &=-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}-\frac {\left (a^2+2 a b-b^2\right ) \sqrt {e} \log \left (\sqrt {e}+\sqrt {e} \cot (c+d x)-\sqrt {2} \sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d}+\frac {\left (a^2+2 a b-b^2\right ) \sqrt {e} \log \left (\sqrt {e}+\sqrt {e} \cot (c+d x)+\sqrt {2} \sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d}-\frac {\left (\left (a^2-2 a b-b^2\right ) \sqrt {e}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} d}+\frac {\left (\left (a^2-2 a b-b^2\right ) \sqrt {e}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} d}\\ &=\frac {\left (a^2-2 a b-b^2\right ) \sqrt {e} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} d}-\frac {\left (a^2-2 a b-b^2\right ) \sqrt {e} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} d}-\frac {4 a b \sqrt {e \cot (c+d x)}}{d}-\frac {2 b^2 (e \cot (c+d x))^{3/2}}{3 d e}-\frac {\left (a^2+2 a b-b^2\right ) \sqrt {e} \log \left (\sqrt {e}+\sqrt {e} \cot (c+d x)-\sqrt {2} \sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d}+\frac {\left (a^2+2 a b-b^2\right ) \sqrt {e} \log \left (\sqrt {e}+\sqrt {e} \cot (c+d x)+\sqrt {2} \sqrt {e \cot (c+d x)}\right )}{2 \sqrt {2} d}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in
optimal.
time = 0.57, size = 220, normalized size = 0.76 \begin {gather*} -\frac {\sqrt {e \cot (c+d x)} \left (4 \left (a^2-b^2\right ) \cot ^{\frac {3}{2}}(c+d x) \, _2F_1\left (\frac {3}{4},1;\frac {7}{4};-\cot ^2(c+d x)\right )+b \left (6 \sqrt {2} a \text {ArcTan}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )-6 \sqrt {2} a \text {ArcTan}\left (1+\sqrt {2} \sqrt {\cot (c+d x)}\right )+24 a \sqrt {\cot (c+d x)}+4 b \cot ^{\frac {3}{2}}(c+d x)+3 \sqrt {2} a \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )-3 \sqrt {2} a \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )\right )\right )}{6 d \sqrt {\cot (c+d x)}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.57, size = 321, normalized size = 1.11
method | result | size |
derivativedivides | \(-\frac {2 \left (\frac {b^{2} \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{3}+2 a b e \sqrt {e \cot \left (d x +c \right )}+e^{2} \left (-\frac {a b \left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{4 e}+\frac {\left (a^{2}-b^{2}\right ) \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (e^{2}\right )^{\frac {1}{4}}}\right )\right )}{d e}\) | \(321\) |
default | \(-\frac {2 \left (\frac {b^{2} \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{3}+2 a b e \sqrt {e \cot \left (d x +c \right )}+e^{2} \left (-\frac {a b \left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{4 e}+\frac {\left (a^{2}-b^{2}\right ) \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (e^{2}\right )^{\frac {1}{4}}}\right )\right )}{d e}\) | \(321\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.52, size = 192, normalized size = 0.67 \begin {gather*} -\frac {{\left (6 \, \sqrt {2} {\left (a^{2} - 2 \, a b - b^{2}\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) + 6 \, \sqrt {2} {\left (a^{2} - 2 \, a b - b^{2}\right )} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) - 3 \, \sqrt {2} {\left (a^{2} + 2 \, a b - b^{2}\right )} \log \left (\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right ) + 3 \, \sqrt {2} {\left (a^{2} + 2 \, a b - b^{2}\right )} \log \left (-\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right ) + \frac {48 \, a b}{\sqrt {\tan \left (d x + c\right )}} + \frac {8 \, b^{2}}{\tan \left (d x + c\right )^{\frac {3}{2}}}\right )} e^{\frac {1}{2}}}{12 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {e \cot {\left (c + d x \right )}} \left (a + b \cot {\left (c + d x \right )}\right )^{2}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.21, size = 1157, normalized size = 4.02 \begin {gather*} -\frac {2\,b^2\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{3/2}}{3\,d\,e}-\frac {4\,a\,b\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{d}-\mathrm {atan}\left (\frac {a^4\,e^4\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,\sqrt {\frac {a^3\,b\,e}{d^2}-\frac {a\,b^3\,e}{d^2}-\frac {a^4\,e\,1{}\mathrm {i}}{4\,d^2}-\frac {b^4\,e\,1{}\mathrm {i}}{4\,d^2}+\frac {a^2\,b^2\,e\,3{}\mathrm {i}}{2\,d^2}}\,32{}\mathrm {i}}{\frac {16\,a^6\,e^5}{d}-\frac {16\,b^6\,e^5}{d}+\frac {112\,a^2\,b^4\,e^5}{d}-\frac {112\,a^4\,b^2\,e^5}{d}+\frac {a\,b^5\,e^5\,32{}\mathrm {i}}{d}+\frac {a^5\,b\,e^5\,32{}\mathrm {i}}{d}-\frac {a^3\,b^3\,e^5\,192{}\mathrm {i}}{d}}+\frac {b^4\,e^4\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,\sqrt {\frac {a^3\,b\,e}{d^2}-\frac {a\,b^3\,e}{d^2}-\frac {a^4\,e\,1{}\mathrm {i}}{4\,d^2}-\frac {b^4\,e\,1{}\mathrm {i}}{4\,d^2}+\frac {a^2\,b^2\,e\,3{}\mathrm {i}}{2\,d^2}}\,32{}\mathrm {i}}{\frac {16\,a^6\,e^5}{d}-\frac {16\,b^6\,e^5}{d}+\frac {112\,a^2\,b^4\,e^5}{d}-\frac {112\,a^4\,b^2\,e^5}{d}+\frac {a\,b^5\,e^5\,32{}\mathrm {i}}{d}+\frac {a^5\,b\,e^5\,32{}\mathrm {i}}{d}-\frac {a^3\,b^3\,e^5\,192{}\mathrm {i}}{d}}-\frac {a^2\,b^2\,e^4\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,\sqrt {\frac {a^3\,b\,e}{d^2}-\frac {a\,b^3\,e}{d^2}-\frac {a^4\,e\,1{}\mathrm {i}}{4\,d^2}-\frac {b^4\,e\,1{}\mathrm {i}}{4\,d^2}+\frac {a^2\,b^2\,e\,3{}\mathrm {i}}{2\,d^2}}\,192{}\mathrm {i}}{\frac {16\,a^6\,e^5}{d}-\frac {16\,b^6\,e^5}{d}+\frac {112\,a^2\,b^4\,e^5}{d}-\frac {112\,a^4\,b^2\,e^5}{d}+\frac {a\,b^5\,e^5\,32{}\mathrm {i}}{d}+\frac {a^5\,b\,e^5\,32{}\mathrm {i}}{d}-\frac {a^3\,b^3\,e^5\,192{}\mathrm {i}}{d}}\right )\,\sqrt {-\frac {1{}\mathrm {i}\,e\,a^4-4\,e\,a^3\,b-6{}\mathrm {i}\,e\,a^2\,b^2+4\,e\,a\,b^3+1{}\mathrm {i}\,e\,b^4}{4\,d^2}}\,2{}\mathrm {i}+\mathrm {atan}\left (\frac {a^4\,e^4\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,\sqrt {\frac {a^3\,b\,e}{d^2}-\frac {a\,b^3\,e}{d^2}+\frac {a^4\,e\,1{}\mathrm {i}}{4\,d^2}+\frac {b^4\,e\,1{}\mathrm {i}}{4\,d^2}-\frac {a^2\,b^2\,e\,3{}\mathrm {i}}{2\,d^2}}\,32{}\mathrm {i}}{\frac {16\,b^6\,e^5}{d}-\frac {16\,a^6\,e^5}{d}-\frac {112\,a^2\,b^4\,e^5}{d}+\frac {112\,a^4\,b^2\,e^5}{d}+\frac {a\,b^5\,e^5\,32{}\mathrm {i}}{d}+\frac {a^5\,b\,e^5\,32{}\mathrm {i}}{d}-\frac {a^3\,b^3\,e^5\,192{}\mathrm {i}}{d}}+\frac {b^4\,e^4\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,\sqrt {\frac {a^3\,b\,e}{d^2}-\frac {a\,b^3\,e}{d^2}+\frac {a^4\,e\,1{}\mathrm {i}}{4\,d^2}+\frac {b^4\,e\,1{}\mathrm {i}}{4\,d^2}-\frac {a^2\,b^2\,e\,3{}\mathrm {i}}{2\,d^2}}\,32{}\mathrm {i}}{\frac {16\,b^6\,e^5}{d}-\frac {16\,a^6\,e^5}{d}-\frac {112\,a^2\,b^4\,e^5}{d}+\frac {112\,a^4\,b^2\,e^5}{d}+\frac {a\,b^5\,e^5\,32{}\mathrm {i}}{d}+\frac {a^5\,b\,e^5\,32{}\mathrm {i}}{d}-\frac {a^3\,b^3\,e^5\,192{}\mathrm {i}}{d}}-\frac {a^2\,b^2\,e^4\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,\sqrt {\frac {a^3\,b\,e}{d^2}-\frac {a\,b^3\,e}{d^2}+\frac {a^4\,e\,1{}\mathrm {i}}{4\,d^2}+\frac {b^4\,e\,1{}\mathrm {i}}{4\,d^2}-\frac {a^2\,b^2\,e\,3{}\mathrm {i}}{2\,d^2}}\,192{}\mathrm {i}}{\frac {16\,b^6\,e^5}{d}-\frac {16\,a^6\,e^5}{d}-\frac {112\,a^2\,b^4\,e^5}{d}+\frac {112\,a^4\,b^2\,e^5}{d}+\frac {a\,b^5\,e^5\,32{}\mathrm {i}}{d}+\frac {a^5\,b\,e^5\,32{}\mathrm {i}}{d}-\frac {a^3\,b^3\,e^5\,192{}\mathrm {i}}{d}}\right )\,\sqrt {\frac {1{}\mathrm {i}\,e\,a^4+4\,e\,a^3\,b-6{}\mathrm {i}\,e\,a^2\,b^2-4\,e\,a\,b^3+1{}\mathrm {i}\,e\,b^4}{4\,d^2}}\,2{}\mathrm {i} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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